00:01
Hello everyone, we are going to understand this question here given in the question angle theta is equal to 28 degree at which force is applied and coefficient of static friction coefficient of static friction that is represented by mu s which is 0 .4 and coefficient of kinetic friction coefficient of kinetic friction that is represented by mu k which is 0 .3 and applied force applied force f is equal to 13 newton so here we have to find the mass of the box mass of box that is represented by m which we have to find let this is block, let's draw the free body diagram.
01:33
Here weight of the block is working vertically downward, this will be balanced by the friction force.
01:39
And here applied force is f.
01:41
So horizontal component is f cost 28 and vertical component is f sign 28.
01:47
So we can write n is equal to f cost 28.
01:57
This will be the normal reaction on the block.
02:01
And it is in balance condition so m g is equal to f sine 28 plus frictional force or we can write m g is equal to f sine 28 plus here value of friction force is not given so here we can write mu into f into cost 28 now we can write m is equal to f sine 28 plus mu into f into cost 28 upon g so substituting the value in this now substituting the value in this m is equal to value of f is 13 into sine 28 into value of mu that is 0 .4 into value of f is 13 into cost 28.
03:31
Here it is clearly given that if force means block is sliding in downward direction, means there is, if we will apply the 13 newton force, then it will just stop...