A small object of mass 3.80 g and charge of -18 µC is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. What is the magnitude and direction of the electric field? Please include a diagram.
Added by Jason W.
Step 1
80 g = 0.0038 kg - Charge of the object, q = -18 µC = -18 × 10^-6 C - Acceleration due to gravity, g = 9.8 m/s^2 ** Show more…
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