A small truck has a mass of 2100 kg. How much work is required to decrease the speed of the vehicle from 22.0 m/s to 12.0 m/s on a level road?
Added by Anil K.
Step 1
0 m/s. The formula for kinetic energy is 1/2 * mass * velocity^2. So, the initial kinetic energy is 1/2 * 2100 kg * (22.0 m/s)^2 = 514200 Joules. Show more…
Show all steps
Your feedback will help us improve your experience
Prabhu Ramji and 70 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A small truck has a mass of $2100 \mathrm{~kg}$. How much work is required to decrease the speed of the vehicle from $22.0 \mathrm{~m} / \mathrm{s}^{22.0 \mathrm{~m} / \mathrm{s}}$ to $12.0 \mathrm{~m} / \mathrm{s}^{12.0 \mathrm{~m} / \mathrm{s}}$ on a level road? Example 6-4
A small truck has a mass of 2100-kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on a level road. Find the magnitude of the required work. Express answer in 2 significant figures in KJ in scientific notation.
Prabhu R.
Pritesh R.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD
