A soft tennis ball is dropped onto a hard floor from a...

A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.05 m. (Assume that the positive direction is upward.) (a) Calculate its velocity just before it strikes the floor. m/s (b) Calculate its velocity just after it leaves the floor on its way back up. m/s (c) Calculate its acceleration during contact with the floor if that contact lasts 3.50 ms. m/s2 (d) How much did the ball compress during its collision with the floor, assuming the floor is absolutely rigid? m

Transcript

00:01 Hi, in this question the height of falling of the tennis ball h1 is given as 1 .5 meters.

00:14 Then the rebounding height, let it be h2, is given as 1 .05 meters.

00:23 We need to determine the velocity of the ball just before it strikes the ground, that is v1.

00:33 Just before the ball strikes the ground.

00:38 Then we need to find the velocity of the ball just after it leaves the floor.

00:46 Then we need to determine the acceleration a during the contact with the floor.

00:55 If the contact time, if the contact time t is 3 .5 milliseconds, 10 power minus 3 .3.

01:07 Seconds.

01:09 Then we need to determine the compression of the ball x.

01:14 Now let us determine the velocity of the ball just before it strikes the ground.

01:21 That is v1.

01:23 B1 can be determined by using the relation square root of 2g h1.

01:29 Now let us plug the given values square root of 2 in 9 .81 meter per second square multiply with height is 1 .5 meters.

01:42 On calculation we obtained v1 is equal to 5 .42 meters per second.

01:56 This is the velocity of the ball just before it strikes the ground.

02:02 Now let us determine the velocity of the ball just after it leaves the ground.

02:07 That is v2.

02:08 V2 also can be determined by using the same relation except this h1 must be h2.

02:19 Now let us plug the given values and determine the value of v2.

02:24 Square root of 2 multiply with 9 .8, multiply with 1 .05.

02:34 On calculation we obtained the velocity of the ball just after it leaves the ground, v2 is equal to 4 .54 meters per second.

02:51 Now let us go into the part c...

Question

Please give Ace some feedback