0:00
All right, hello.
00:01
In this question, we're given this setup where we have an object of mass m sitting on a wheel, solid wheel, of mass m.
00:10
And we're told it's released from us, so this object moves down.
00:14
And once it's at the bottom down here, it will be traveling, obviously, to the left and with some speed.
00:20
And we want to know when that happens, this whole wheel will be spinning, what is omega final going to be? we know that the omega 0 is equal to 0.
00:28
Well, in order to do this, we're going to use conservation of energy.
00:32
Seems like a good approach.
00:34
And so initially, what do we have? well, we have this mass, and it's elevated some distance h above where it's going to end up.
00:43
We also have mass stored in this disk.
00:48
But the center of mass of the disk doesn't actually change how high it is, so we don't have to worry about gravitational potential of that.
00:56
So we just have gravitational potential of the point mass, initially.
00:59
And at the end, we have the point mass, which is moving with a linear speed, 1 half mv.
01:06
So we have kinetic energy of the point mass.
01:09
It's not itself actually rotating at all, but the wheel is.
01:14
So we also have rotational kinetic energy of the wheel.
01:18
So let's go ahead and expand this out.
01:20
We're going to have m times g times h.
01:22
The particle is moving 1 half mv squared.
01:26
At the bottom, that's v final.
01:27
And then the object is rotating with 1 half i omega final squared.
01:33
Ok, well, we've got to clean this up a little bit.
01:36
So first off, we need to figure out what h is...