The volume of the sphere is given by:
$V = \frac{4}{3}\pi r^3$
where $r = 40.0\,\text{cm} = 0.4\,\text{m}$. So,
$V = \frac{4}{3}\pi (0.4)^3 = 0.268\,\text{m}^3$
The total charge is $Q = 42.8\,\text{µC} = 42.8 \times 10^{-6}\,\text{C}$. The charge density
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