A solid, uniform sphere of mass 2.0 kg and radius 1.7m rolls without slipping down an inclined plane of height 5.3m What is the angular velocity of the sphere at the bottom of the inclined plane? A.9.7 rad/s B.5.1 rad/s C.6.1 rad/s D.8.7 rad/s
Added by Jeffery R.
Step 1
This is given by mgh, where m is the mass of the sphere, g is the acceleration due to gravity, and h is the height of the inclined plane. So, the initial potential energy is (2.0 kg)(9.8 m/s^2)(5.3 m) = 103.76 J. As the sphere rolls down the inclined plane Show more…
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