A solution buffered at pH 5.2 is needed for a reaction using CH3COOH/CH3COONa. what ratio of moles of the conjugate base anion (CH3COO-) to the acid (CH3COOH) is needed? Ka of the acid = 1.8 Ă— 10^-5 2.88 0.34 0.46 2.11
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We are given that the pH is 5.2 and the Ka of the acid is 1.8 x 10^-5. We can calculate the pKa from the Ka using the equation: pKa = -log(Ka) Substituting the given Ka into this equation gives: pKa = -log(1.8 x 10^-5) = 4.74 Now we can substitute the given Show more…
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