0:00
Good day.
00:01
In this question, we will be solving the ph, p -o -h, or the o -h -minus concentration with the given.
00:08
So for the first one, given p -o -h is equals to 2 .29, we are asked to solve for the o -h -minus concentration, which is equals to 10 to the negative p -o -h.
00:22
We have 10 to the negative 2 .29.
00:25
Therefore, o -h -h -h -mines concentration is equals to 5 .13 times 10 to the negative 3 m next for number 2 we are asked to solve for the oh h minus also given that ph is equal to 10 .21 therefore we need to solve for p .o .h first, which is 14 minus ph, equals 14 minus 10 .21.
01:13
This is equals to 3 .79, solving for o .h minus concentration, which is also equals to 10 to the negative p .o .h, 10 to the negative 0 .10 to the negative 3 .79.
01:31
Therefore, this is equals to 1 .62 times 10 to the negative 4 .4.
01:40
M.
01:43
For number three, we are given the ph and what is poh...