A solution is made by dissolving 30.7 g of $Ba(NO_2)_2$ in 500.0 mL of water. What is the value of Kb for $NO_2^-$? The Ka of $HNO_2$ is $4.5 \times 10^{-4}$.
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We can use the relationship between Ka and Kb for a conjugate acid-base pair: $K_w = K_a \times K_b$ where $K_w$ is the ion product of water, which is $1.0 \times 10^{-14}$ at 25°C. Show more…
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