A solution is made by mixing 111.g of benzene C6H6 and 145.g of acetyl bromide CH3COBr Calculate the mole fraction of benzene in this solution. Be sure your answer has the correct number of significant digits.
Added by Jose Carlos L.
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11 g/mol Number of moles of benzene = 111 g / 78.11 g/mol = 1.42 mol Show more…
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