A solution is prepared by dissolving 67.8 g of sucrose, C12H22O11, (MM = 342.34 g/mol) in 0.516 kg of water. The final volume of the solution is 355 mL. Calculate the molality of the solution.
Added by Nicole L.
Step 1
We do this by dividing the mass of the sucrose by its molar mass: 67.8 g / 342.34 g/mol = 0.198 mol Show more…
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