Question

A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)2,(aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 18.52 g PbCI2, (s) is obtained from 200.0 mL of the original solution. Calculate the molarity of the Pb(NO3)2, (aq) solution.

Name: a solution of naclaq is added slowly to a solution of lead nitrate pbno32aq until no further precipitation occurs the precipitate is collected by filtration dried and weighed a total of 1852 84948
Uploaded: 2021-10-12T08:15:58-08:00
Duration: 2 min 55 s
Channel: Adriano Chikande
Description: a solution of naclaq is added slowly to a solution of lead nitrate pbno32aq until no further precipitation occurs the precipitate is collected by filtration dried and weighed a total of 1852 84948

          A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)2,(aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 18.52 g PbCI2, (s) is obtained from 200.0 mL of the original solution.
Calculate the molarity of the Pb(NO3)2, (aq) solution.

Added by Matthew G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adriano Chikande

10/12/2021

Step 1

The reaction is: \[ \text{Pb(NO}_3\text{)}_2 (aq) + 2 \text{NaCl} (aq) \rightarrow \text{PbCl}_2 (s) + 2 \text{NaNO}_3 (aq) \] This shows that 1 mole of Pb(NO3)2 reacts with 2 moles of NaCl to produce 1 mole of PbCl2. Show more…

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A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)2,(aq), until no further precipitation occurs. The precipitate is collected by filtration, dried, and weighed. A total of 18.52 g PbCI2, (s) is obtained from 200.0 mL of the original solution. Calculate the molarity of the Pb(NO3)2, (aq) solution.