00:01
In this problem we have a vertical car ride in the loop the loop ride and it is in vertical plane and the radius of circle is given and when the person sits on the ride and the ride is stationary thus reading of sensor is given and the sensor reading at the top of the ride is also given and the sensor reading at the top of the ride is also given and and we have to find out the speed of the rider at the top of the loop.
00:38
Now, when the ride is level and stationary, we draw the free body diagram of the rider.
00:56
Upward force is the normal force, which is equal to the reading and downward is the weight.
01:04
So, in stationary position, normal force must be equal to weight of the body.
01:18
So this is 790 newton and mass is unknown and g is 9 .8 meter per second square.
01:27
This gives us mass m equal to 80 .6 kilogram.
01:36
Now at the top of the loop, the normal force on the seat will be downwards and the weight will also be downward, which is mg.
01:58
So the equation of motion for normal force, sorry for the rider at the top is n -not plus m -g and they give the centripetal force which is nv squared upon r...