00:01
This question is about the binormal distribution.
00:03
Let me just take notes.
00:04
So the probability was given as 8%.
00:07
This is the probability of a part is defective.
00:10
So i can just write this is 0 .08.
00:13
So for part a, so for the first part, it says the problem that the fourth part retrieved from the stock is the first defective.
00:23
So that means so no defective from the first three part and then defective.
00:30
So we need to get the probability of x is equal to zero.
00:34
So be careful, the three defective or the three parts we have.
00:38
So i'm going to use that this is three zero combination times 0 .08 to the power of, this is power of zero, and times 1 minus 08 to the power of 3 minus 0, which is 3.
00:50
Let me just make a recall here.
00:52
I'm going to use this formula, which is nx combination times p to the power x and 1 minus p to the power x and minus p.
01:01
X here.
01:02
Let me just do this calculation.
01:04
So 3 -0 combination is 1, 0 .08 to the power 0, which is 1, and we have 0 .92 to the power 3, which is 0 .92 to the power of 3...