00:01
It is given that she started to walk towards west and covered the distance of 130 meters.
00:09
I am taking the positive x -axis as positive i -cap, negative as minus negative i -cap.
00:15
The same way, y, positive j -cap and minus y negative j -cap.
00:20
So if i consider s -1, this as s -1, so my s -1 vector will become minus 130 i of i -cap.
00:28
The same way, if this is s2, which is at 45 degrees east of south, this is east, west, north, and south, okay, this is east of south.
00:47
This is 45.
00:48
And again, she traveled towards 30 degrees east of north.
00:56
And then this is the unknown distance as she is back from where she started.
01:03
So if i start from s1, i get my s1 minus 130 icap.
01:08
This is s2.
01:09
I'm breaking this vector into components.
01:12
Y component will be 290 cos of 45 and x component will be 290 sine of 45.
01:22
So i will get my s2 vector as 290 cos 45 i cap minus 29.
01:34
2090 cos 45 j cap this will be 290 sign of 45 i cap x component okay so i will get this as 205 .03 i cap minus 205 .03 j cap as my result of s2 vector now this is s3 so i'm breaking this again into the components.
02:10
The x component will be 280 sign of 30 and the y component will be 280 cos of 30 degrees.
02:22
So my s3 vector will become 280 sign of 30 i cap plus 280 cause of 30 0 .48 jcap.
02:44
Now it is given that the curl is back from where she has started.
02:48
That means the total displacement is 0.
02:51
This is the starting point and this is the ending point as well...