First, we need to find the total charge enclosed by the sphere. To do this, we'll integrate the charge density over the volume of the sphere.
$$Q = \int_{V} \rho dV = \int_{0}^{R} \int_{0}^{\pi} \int_{0}^{2\pi} Cr \cdot r^2 \sin{\theta} dr d\theta d\phi$$
Show moreā¦