00:01
Hello students.
00:03
In this problem, we have a solid sphere of radius capital r and charge capital q.
00:13
Charge is capital q and its radius is capital r and this charge is known uniformly distributed over it.
00:20
And the charge density is given c by r square, coulom per meter cube.
00:29
It is volume charge density, that is charge per end volume.
00:33
Okay first of all we have to calculate the value of c to this to find this value of see what we are doing we are taking a spherical shell of radius r and with d r its thickness is taken as d r its small thickness is taken as d r it means the volume of this shell will be 4 pi r squared here this d r is very minute it is charge on this shell will be charge density c by r square of course we can write it row dv charge of density at r distance into volume of this shell and the volume of this shell is surface area into thickness we are writing this value now dq equals to c by r square c by r square 4 pi r square d r what it is it is a volume of this shell 4 pi r square d r clearly r c r square is canceling out we will cancel this r square of course.
01:39
It means the dq is equal to this dq is equals to c4 pi dr.
01:49
If we calculate total charge in this shell by doing integration, integrating this side from 0 to capital r.
02:00
Integrating this side from 0 to capital r, it will give us total charge capital q, 0 to q.
02:09
Clearly intuition of dr is r after putting limit it will be capital r q equal to c time 4 pi r we were looking for the value of c it means c is equals to it means clearly c is equals to q upon 4 pi r it is our first part of the question calculation of c and we got it the value of c clearly unit will be coulampar it is coulomb per meter.
02:47
Okay.
02:49
It is the value of c.
02:50
Now what we have to do, we have to find the electric field inside this solid sphere and outside this sphere...