00:01
Hello, in the question we have given that a spherical capacitor contains a charge of 3 .3 nano coulomb.
00:09
So, the charge is equal to 3 .3 nano coulombs when connected to a potential difference that is v is equal to 250 volts is given if its plates are separated by vacuum and the inner radius of the outer shell is 5 centimeters.
00:28
So, let us call this as r2 is equal to 5 centimeters.
00:37
So, see this will be the spherical capacitor.
00:40
So, there will be one sphere inside and one sphere outside and this region is filled with vacuum.
00:50
So, outer radius is r2 and the inner radius is r1.
00:55
So, in the first part we have to calculate the radius of inner sphere itself.
01:03
So, we have to calculate r1.
01:06
So, in order to calculate this we will use a relation.
01:14
So, we know that for spherical capacitor, we know that q by v is equal to 4 pi epsilon naught divided by 1 upon r1 minus 1 upon r2.
01:43
So, this equation we get when we solve the potential.
01:52
So, now we will just rearrange this equation.
01:56
So, it will be 1 upon r1 minus 1 upon r2 that is equal to 4 pi epsilon naught q and we will go in the numerator.
02:08
So, we want to find out r1.
02:11
So, 1 upon r1 will be equal to 4 pi epsilon naught v divided by q plus 1 upon r2.
02:21
So, now from here 1 upon r1 will be equal to 4 into 3 .14 into this epsilon naught is 8 .85 into 10 raised to minus 12 into potential difference is.
02:38
So, there will be lack of space.
02:45
So, here from here i will write.
02:49
So, 1 upon r1 will be equal to 4 into 3 .14 into 8 .85 into 10 raised to minus 12 into this potential is given which is of 250 volts divided by q is 3 .3 into 10 raised to minus 9 coulombs plus 1 upon r2.
03:19
R2 is 5.
03:21
So, 5 into 10 raised to minus 2 it will be...