00:02
Okay, so e of c equals to 57 ,000 times square root of f of c.
00:15
And if 6 ,000 psi for f of c, then we know that this is equal to 6 ,000.
00:24
So we have this is equal to 4 .415 times 10 to the 6th over 10.
00:35
And then the 3.
00:38
And then the module ratio of n is going to be equal to es over ec.
00:50
So that's going to be equal to 29 divided by which equals 7 .19, which is approximately 720.
01:13
The concrete module's rupture is f of c equals to 7 .5 times f prime of c and that's the square root.
01:27
So as we know, that's going to be equal to 6 ,000.
01:33
So that's going to be equal to 581 psi.
01:45
Now for compressive strength, we have 0 .45 times that.
01:51
So we're going to have f of c equals 0 .45 times 6 ,000, which equals to 2 ,700 psi.
02:09
So we have f of s equals 0 .60 times 60 ,000, which equals to 36 ,000 psi.
02:29
So the reinforcements are given by p .e...