A square loop of wire with sides of 50.0 cm is oriented at an angle of 30 to a magnetic field of 0.50 T. The current in the loop is 2.0 A in the direction shown (from up to down with respect to the x-axis). What is the magnitude of the torque in this instance?
Added by Eugenia M.
Step 1
Given that the side length of the square loop is 50.0 cm, convert it to meters: Side length = 50.0 cm = 0.50 m Area of the square loop = (side length)^2 = (0.50 m)^2 = 0.25 m^2 Show more…
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