5 A SSB modulator using Weaver's Method is illustrated in Figure 1 below. If the input 8 signal is $m(t) = cos(2\pi f_m t)$, where $f_m < W$, demonstrate that by proper choice of $f_1$ and $f_2$ the output is a SSB signal.
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The input signal is mt = cos(2πfmt), where fm < W. This means that the input signal has a frequency fm that is less than the bandwidth W. Show more…
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4.4-7 A USB signal is generated by using the phase shift method (Fig. 4.17). If the input to this system is mh(t) instead of m(t), what will be the output? Is this signal still an SSB signal with bandwidth equal to that of m(t)? Can this signal be demodulated [to get back m(t)]? If so, how? Figure 4.17 Generating SSB using the phase shift method. DSB-SC modulator m(t) cos ωct cos ωct m(t) SSB signal sin ωct DSB-SC modulator mh(t) sin ωct -π/2
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