Question

A standard CaCO3 solution is prepared by dissolving 0.4193 g in enough dilute HCl to effect solution and then diluted to 500 mL solution. A 25.00-mL aliquot requires 23.62 mL EDTA solution for titration. A 25.00-mL water sample determined for total hardness, requires 8.45 mL of the EDTA solution using Eriochrome Black T as indicator. Calculate the total hardness in the water sample expressed in ppm CaCO3.

Name: A standard CaCO3 solution is prepared by dissolving 0.4193 g in enough dilute HCl to effect solution and then diluted to 500 mL solution. A 25.00-mL aliquot requires 23.62 mL EDTA solution for titration. A 25.00-mL water sample determined for total hardness, requires 8.45 mL of the EDTA solution using Eriochrome Black T as indicator. Calculate the total hardness in the water sample expressed in ppm CaCO3.
Uploaded: 2022-09-02T11:07:25-08:00
Duration: 3 min 32 s
Channel: Adi S

          A standard CaCO3 solution is prepared by dissolving 0.4193 g in enough dilute HCl to effect solution and then diluted to 500 mL solution. A 25.00-mL aliquot requires 23.62 mL EDTA solution for titration. A 25.00-mL water sample determined for total hardness, requires 8.45 mL of the EDTA solution using Eriochrome Black T as indicator. Calculate the total hardness in the water sample expressed in ppm CaCO3.

A standard CaCO3 solution is prepared by dissolving 0.4193 g in enough dilute HCl to effect solution and then diluted to 500 mL solution. A 25.00-mL aliquot requires 23.62 mL EDTA solution for titration. A 25.00-mL water sample determined for total hardness, requires 8.45 mL of the EDTA solution using Eriochrome Black T as indicator. Calculate the total hardness in the water sample expressed in ppm CaCO3.

Added by John S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

09/02/2022

Step 1

The molar mass of CaCO₃ is approximately 100.09 g/mol. \[ \text{Moles of CaCO}_3 = \frac{0.4193 \text{ g}}{100.09 \text{ g/mol}} = 0.00419 \text{ mol} \] Since the solution is diluted to 500 mL (0.500 L): \[ \text{Molarity of CaCO}_3 = \frac{0.00419 \text{ Show more…

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A standard CaCO3 solution is prepared by dissolving 0.4193 g in enough dilute HCl to effect solution and then diluted to 500 mL solution. A 25.00-mL aliquot requires 23.62 mL EDTA solution for titration. A 25.00-mL water sample determined for total hardness, requires 8.45 mL of the EDTA solution using Eriochrome Black T as indicator. Calculate the total hardness in the water sample expressed in ppm CaCO3.