Question

A stationary bicycle is raised off the ground, and its front wheel (m = 2.58 kg) is rotating at an angular velocity of 26.9 rad/s (see the figure). The front brake is then applied for 3.17 s, and the wheel slows down to 4.20 rad/s. Assume that all the mass of the wheel is concentrated in the rim, the radius of which is 0.330 m. The coefficient of kinetic friction between each brake pad and the rim is μk = 0.763. What is the magnitude of the normal force that each brake pad applies to the rim?

          A stationary bicycle is raised off the ground, and its front
wheel (m = 2.58 kg) is rotating at an angular velocity of 26.9
rad/s (see the figure). The front brake is then applied for 3.17 s,
and the wheel slows down to 4.20 rad/s. Assume that all the mass of
the wheel is concentrated in the rim, the radius of which is 0.330
m. The coefficient of kinetic friction between each brake pad and
the rim is μk = 0.763. What is the magnitude of the normal force
that each brake pad applies to the rim?

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Added by Victoria M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

09/15/2023

Step 1

First, we need to find the angular acceleration of the wheel. We can use the formula: $$ \alpha = \frac{\omega_f - \omega_i}{t} $$ where $\omega_f$ is the final angular velocity, $\omega_i$ is the initial angular velocity, and $t$ is the time. Show more…

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A stationary bicycle is raised off the ground, and its front wheel (m = 2.58 kg) is rotating at an angular velocity of 26.9 rad/s (see the figure). The front brake is then applied for 3.17 s, and the wheel slows down to 4.20 rad/s. Assume that all the mass of the wheel is concentrated in the rim, the radius of which is 0.330 m. The coefficient of kinetic friction between each brake pad and the rim is μk = 0.763. What is the magnitude of the normal force that each brake pad applies to the rim?

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