00:01
A pulse is sent to an object down here to certain depth.
00:06
Object is here, let's say.
00:09
And the time delay counted here is 80 milliseconds.
00:15
The frequency with which the signal is received, we will call it fr received, 39 .958 megahertz where the signal incident is 40 megahertz.
00:41
So for the first part of the problem let's find the depth.
00:45
So it will cover a distance let's say from here to here is l.
00:50
It will then cover a distance of 2l.
00:55
This distance will be equal to speed times the time it took.
01:00
So c times from there we can solve for l, so the depth l will be equal to c times t divided by 2.
01:09
C we have is a 15, 40 meter per second, converting kilometers into meters times the t 80 milliseconds.
01:18
That means 80 times 10 to the bow minus 3 divided by 2...