00:01
Here the stress sigma is given which is 280 megapascal or we can say that this is equal to 280 newton per millimeter square because megapascal is equal to newton per millimeter square modulus of elasticity is given which is 205 gigapascal or we can say that this is equal to 205 into 10 power 3 newton per meter square.
00:37
The diameter of the bar is given which is equal to 80mm.
00:43
The cross -sectional area of the bar is equal to the equation is 5 by 4 into d square.
00:50
So this is equal to 5 by 4 into 80 square and this turns out to be 5026 .55.
01:00
Millimeter square.
01:02
The length is given, length of the bar is equal to 240 mm.
01:08
Now in the first part we need to calculate the strain.
01:15
Strain is equal to epsilon is equal to the equation for strain is pressure by area into modulus of elasticity because we know that strain is equal to change in length by original length or this is equal to pressure divided by or stress by modulus of elasticity stress means pressure by area by modulus of elasticity so p divided by a into e is the equation for strain here so here substituting the values here pressure is 280 newton per millimeter square divided by e is 205 into 10 power minus 3.
02:01
Upon solving we will get the value to be 1 .365 into 10 power minus 3.
02:10
Or we can say that this is equal to the value of strain is equal to 0 .001365...