00:01
At 25 degrees celsius and 100 kioskal, the density of steel, row represents the density of steel is equal to 7820 kilogram per meter cube.
00:23
Therefore, volume of steel is equal to, we know that volume is equal to mass divided by density.
00:30
Mass of the steel is given which is 4 kilograms divided by density which is 7820 kilogram per meter cube upon solving this we will get a volume of steel is equal to 0 .0 .30 512 meter cube so this is the volume of steel now density of water at 25 degrees celsius and 100 kiosklae is is taken to be 997 kilogram per meter cube.
01:09
So mass of water will be equal to, we know that mass will be equal to density into volume.
01:18
Given 4 liter, we know that 1 liter is equal to 0 .001 meter cube.
01:26
Therefore 4 liter will be equal to 0 .004 meter cube.
01:33
So here we have to convert litter into meter cube.
01:37
So mass of water will be equal to density of water which is 997 kilogram per meter cube into the volume which is 0 .004 meter cube.
01:51
Upon solving this we will get a mass of water to be 3 .98 kilogram.
01:59
Now we need to determine the total mass.
02:05
Total mass m is equal to mass of steel plus mass of water, which is equal to mass of steel is given which is 4 kilogram.
02:20
Mass of water we have found out which is 3 .98 kilogram.
02:25
So the total mass will become 7 .9 double.
02:31
So this is the value for total mass.
02:37
Now next we need to calculate the value of total volume.
02:43
Total volume v is equal to volume of steel plus volume of water...