"A steel rod of length 1 m and radius 10 mm is stretched by a force 100 kN along its length. The elongation produced in the rod is (YSteel = 2 × 1011 N m–2)"
Added by Zooko D.
Step 1
Given: Force (F) = 100 kN = 100,000 N Radius (r) = 10 mm = 10^-2 m Area (A) = πr^2 = π(10^-2)^2 = π(10^-4) = 10^-4π Stress (σ) = F / A σ = 100,000 / (10^-4π) σ = 10^5 / (10^-4π) σ = 10^9 / π Show more…
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