a steel wire of length 197 m with circular cross section must stretch no more than 0300 cm when

Name: a steel wire of length 197 m with circular cross section must stretch no more than 0300 cm when a tensile stretching force of 410 n is applied to each end of the wire what minimum diameter d 91868
Uploaded: 2022-05-03T18:18:41-08:00
Duration: 2 min 9 s
Channel: Madhur L
Description: a steel wire of length 197 m with circular cross section must stretch no more than 0300 cm when a tensile stretching force of 410 n is applied to each end of the wire what minimum diameter d 91868

Step 1: Calculate the area of the wire using the formula A = F * L / (Y * ΔL), where F is the fo

Question

A steel wire of length 1.97 m with a circular cross-section must stretch no more than 0.300 cm when a tensile (stretching) force of 410 N is applied to each end of the wire. What minimum diameter dmin is required for the wire? Express your answer in millimeters. Take Young's modulus for steel to be Y = 2.00×10^11 Pa.

          A steel wire of length 1.97 m with a circular cross-section must stretch no more than 0.300 cm when a tensile (stretching) force of 410 N is applied to each end of the wire.
What minimum diameter dmin is required for the wire?
Express your answer in millimeters. Take Young's modulus for steel to be Y = 2.00×10^11 Pa.

Added by Kim M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

05/03/2022

Step 1

97 m), Y is Young's modulus for steel (2.00 x 10^11 Pa), and ΔL is the maximum allowable stretch (0.300 cm = 0.003 m). Plugging in the values: A = (410 * 1.97) / (2.00 x 10^11 * 0.003) A = 0.13462 x 10^-6 m^2 Show more…

Show all steps

Thanks for your feedback!

A steel wire of length 1.97 m with a circular cross-section must stretch no more than 0.300 cm when a tensile (stretching) force of 410 N is applied to each end of the wire. What minimum diameter dmin is required for the wire? Express your answer in millimeters. Take Young's modulus for steel to be Y = 2.00×10^11 Pa.