a steel wire of length 200 m with circular cross section must stretch no more than 0210 cm when

Name: a steel wire of length 200 m with circular cross section must stretch no more than 0210 cm when a tensile stretching force of 410 n is applied to each end of the wire what minimum diameter d 68397
Uploaded: 2022-06-09T10:25:31-08:00
Duration: 2 min 4 s
Channel: Madhur L
Description: a steel wire of length 200 m with circular cross section must stretch no more than 0210 cm when a tensile stretching force of 410 n is applied to each end of the wire what minimum diameter d 68397

Step 1: Calculate the area of the cross-section of the wire using the formula A = F * L / (Y * d

Question

A steel wire of length 2.00 m with a circular cross-section must stretch no more than 0.210 cm when a tensile (stretching) force of 410 N is applied to each end of the wire. What is the minimum diameter (dmin) required for the wire? Express your answer in millimeters. Take Young's modulus for steel to be Y = 2.00×10^11 Pa.

          A steel wire of length 2.00 m with a circular cross-section must stretch no more than 0.210 cm when a tensile (stretching) force of 410 N is applied to each end of the wire. What is the minimum diameter (dmin) required for the wire? Express your answer in millimeters. Take Young's modulus for steel to be Y = 2.00×10^11 Pa.

Added by Micheal J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

06/09/2022

Step 1

00 m), Y is Young's modulus for steel (2.00 x 10^11 Pa), and delta is the maximum allowable stretch (0.210 cm = 0.0021 m). Show more…

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A steel wire of length 2.00 m with a circular cross-section must stretch no more than 0.210 cm when a tensile (stretching) force of 410 N is applied to each end of the wire. What is the minimum diameter (dmin) required for the wire? Express your answer in millimeters. Take Young's modulus for steel to be Y = 2.00×10^11 Pa.