A stone is dropped into a well in which the level of water is h below, the top of the well. If v is velocity of sound, then time T after which the splash is heard is equal to
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Step 1
Step 1: When the stone is dropped, it falls freely under gravity, so its motion can be described by the equation h = (1/2) g tāĀ², where h is the depth of the water, g is the acceleration due to gravity, and tā is the time taken by the stone to fall. Show moreā¦
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A stone is dropped into a well in which the level of water is $h$ below the top of the well. If $v$ is velocity of sound, the time $T$ after which the splash is heard is given by: (a) $T=2 h / v$ (b) $T=\sqrt{\left(\frac{2 h}{g}\right)}+\frac{h}{v}$ (c) $T=\sqrt{\left(\frac{2 h}{v}\right)}+\frac{h}{\mathrm{~g}}$ (d) $T=\sqrt{\left(\frac{h}{2 g}\right)}+\frac{2 h}{v}$
KINEMATICS
Motion in a Straight Line
" A stone is dropped into a well in which the level of water is h below the top of the well. If v is velocity of sound, the time T after which the splash is heard is given by."
Dharmendra M.
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