A stone is thrown upward. It returns to the ground after 3 seconds. 1. What is the maximum height reached by the stone? 2. What is the initial velocity of the stone? 3. What is the speed of the stone as it hits the ground? 4. How long will it take to reach the ground?
Added by Albert H.
Step 1
- Total time of flight, \( T = 3 \) seconds. - Acceleration due to gravity, \( g = 9.8 \, \text{m/s}^2 \). The relevant equations are: Show more…
Show all steps
Close
Your feedback will help us improve your experience
Suman K and 80 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
"A piece of stone is thrown vertically upwards. It reaches the maximum height in 3 seconds. If the acceleration of the stone be 9.8 m/s^2 directed towards the ground, calculate the initial velocity of the stone with which it is thrown upwards"
Jaya M.
A stone thrown vertically upward with a velocity of 4.9 m per second. 1) The maximum height reached is 1.225 m. 2) The time taken to reach the maximum height is 0.5 seconds. 3) The velocity with which it returns to the ground is 4.9 m per second. 4) The time taken to reach the ground is 1 second.
Sri K.
(III) A stone is thrown vertically upward with a speed of 12.0 $\mathrm{m} / \mathrm{s}$ from the edge of a cliff 70.0 $\mathrm{m}$ high (Fig. $2-34 )$. (a) How much later does it reach the bottom of the cliff? (b) What is its speed just before hitting? (c) What total distance did it travel?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD