A stone is thrown vertically upward with an initial velocity of 49 m/s. a) How high does the stone go? b) How long does it take to reach the highest point? c) At what time will the stone be at 100 m from the ground?
Added by Encarnacion M.
Step 1
8 m/s^2) s = displacement (maximum height reached) Rearranging the equation, we have: s = (v^2 - u^2) / (2a) Plugging in the values, we get: s = (0^2 - 49^2) / (2 * -9.8) s = (-2401) / (-19.6) s = 122.5 meters Show more…
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