"A straight wire of mass 200 g and length 1.5 m carries a current of 2A. It is suspended in mid air by a uniform magnetic field B. What is the magnitude of the magnetic field?"
Added by Shirlin S.
Step 1
Given formula: \( F = BIL \) Substitute the values: \( F = 2 \times B \times 1.5 \) \( F = 3B \) Show more…
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A straight wire of mass $200 \mathrm{gm}$ and length $1.5 \mathrm{~m}$ carries a current of $2 \mathrm{~A}$. It is suspended in mid-air by a uniform horizontal magnetic field $B$. The magnitude of $B$ (in tesla) is $$ \left(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\right) $$ (A) 2 (B) $1.5$ (C) $0.55$ (D) $0.66$
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