00:01
So to solve for this, let us try first to balance equation for this reaction.
00:05
We have zinc, then we have silver.
00:08
It's silver nitrate, so age, we n -o -3, and this will produce a zinc nitrate.
00:20
That's n -o -v -2, and then we add silver.
00:25
Okay, so that's the equation, but we need to balance this first.
00:30
Since we have 2 and 03 on the right, we need to right here too.
00:36
So that means we need to write 2 also.
00:38
Okay, so that's the balance equation and let's identify first the limiting reactants.
00:46
So it should be our editor for 8.
00:49
It is the balanced equation and then let's identify the limiting reactant by calculating the number of most of which reactants.
00:57
For of most of zinc, we have 2 grams of zinc.
01:00
Convert that to moles by dividing the atomic mass of zinc that's 65 .38 grams per mole.
01:07
So you'll get 0 .0306 moles and then a number of moles have silver nitrate gno3 that's 2 .50 grams.
01:22
And the motor mass of this compound is 169 .87 grams per mole.
01:31
That means you have 0 .047 mode.
01:34
And how do we get the mole fraction for the limiting reactants? so we'll solve for the mole ratio.
01:43
So mole ratio in this case will be the number of moles of the reactants should be zinc.
01:48
Number of most of the reactants divided by its psychometric coefficient in the balance equation.
01:53
So we have 0 .0366 .6 of zinc divided by the psychometric coefficient of zinc in the balance equation that's going to be 1.
02:02
Okay, so we will divide us by 1.
02:05
You'll still get 0 .0306.
02:08
And then for 820 and 03, we have 0 .047 divided by the second metric coefficient of silver nitrate bets.
02:18
As you can see here, we have 2.
02:19
So we will divide us by 2 and we'll get, it should be 7 .35, very small now.
02:27
It's 7 .35 times 10 to the negative 3...