00:01
We have 5 .5 mil liters of acetic acid, and i think they mean vinegar.
00:22
And it's titrated by 20 .1 mil liters of 0 .1 molar n -a -o -h.
00:35
So we're going to answer our questions.
00:37
A, number of moles of n -a -o -h.
00:45
And that will be moles of n -a -o -h.
00:51
Will equal 20 .1 millimeters times 1 ,000 millimeters per liter, times 0 .110 moles per liter, will equal 0 .002211 moles.
01:26
And that will be to the correct number of sig figs.
01:40
B, moles of acetic acid.
01:48
Oh, i forgot.
01:48
This is actually b.
01:52
A is the balanced chemical equation.
01:57
I missed one.
02:02
That'll be c -h -3 -c -o -o -h.
02:07
That's acetic acid, plus sodium hydroxide.
02:15
My products will be and water.
02:29
Okay.
02:32
So now i can do, that's a, that's b, and now we can do c, which is moles of acetic acid.
02:45
And since it's a one -to -one ratio, and i'm going to abbreviate acetic acid.
03:04
I'll wait.
03:05
I only have to do this this time.
03:18
This is a one -to -one mole ratio.
03:58
Okay, so there's abc.
04:00
And now d is the molarity of acetic acid.
04:12
And for molarity equals moles per liter.
04:17
And i know how many moles of acetic acid we just had.
04:20
We had 0 .00221 moles.
04:28
And we'll divide that by, i think it was 5 .5...