00:01
So here we know that first we want to find the mechanical energy released by 0 .45 kilograms of fat.
00:07
So for part a, we can say that 0 .45 kilograms of fat multiplied by 3 .77 times 10 to the 7 joules of chemical energy per kilogram of fat.
00:22
This is going to be equalling to 16 ,965 ,000 joules.
00:28
Now, we can say that the mechanical energy from this fat would be equaling 20 % of the chemical energy.
00:37
So we can say 20%, or better yet, 0 .20.
01:03
So here we know that first we want to find the mechanical energy released by 0 .45 kilograms of fat.
01:11
So for part a, we can say that zero multiplied by the chemical energy, 16 ,965 ,000 joules.
01:23
And we find that then the mechanical energy released by 0 .45 kilograms of fat, 3 ,393 ,000 joules.
01:36
This would be our final answer for part a.
01:39
For part b, then, we want to lose 0 .45 kilograms of fat.
01:43
Now, we can say that the mechanical energy, 0 .45 kilograms of fat, multiplied by 3 .77 times 10 to the 7th joules of chemical energy per kilogram of fat, this is going to be equaling to 16 ,965 ,000 joules.
02:05
Now, we can say that the mechanical energy from this fat would be equalling 20 % of the chemical energy...