A student is solving the equation 15+3(x−1)=12x+9
. Which describes a first step the student could use to solve the equation correctly?
Responses
The student can distribute 3
on the left side of the equation, resulting in 15+3x−3=12x+9
.
The student can distribute 3 on the left side of the equation, resulting in 15 + 3 x − − 3 = 12 x + 9 .
The student can distribute 3
on the left side of the equation, resulting in 15x+3x+3=12x+9
.
The student can distribute 3 on the left side of the equation, resulting in 15 x + 3 x + 3 = 12 x + 9 .
The student can subtract 15
on both sides of the equation, resulting in 3(x−1)=−3x+9
.
The student can subtract 15 on both sides of the equation, resulting in 3 ( x − − 1 ) = − − 3 x + 9 .
The student can subtract 15
on both sides of the equation, resulting in 3(x−1)=12x+24