A student sets up and solves the following equation to solve a problem in solution stoichiometry. Fill in the missing part of the student's equation. $frac{(2.10 frac{g}{mL})(frac{1 ext{ mL}}{10^{-3} ext{ L}})}{(81.54 ext{oxed{}})} = 25.8 frac{mol}{L}$
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If 2.10 mL is the volume of the solution and X is the molarity in mol/L, then the equation would be: 2.10 mL * (1 L / 1000 mL) * X mol/L = Y mol Show more…
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