00:01
All right, so here in the given question, it says that a supermarket selected a sample of 200 of its customers and measured how long they took to be served at the checkout counter.
00:15
Now, if too many customers wait too long, the supermarket intends to hire more checkout personnel.
00:20
Now, specifically, the supermarket would like at least 90 % of its customer to be checkout in nine minutes or less.
00:27
Now from the data, the 90th and 60th percentile were computed to be 9 .7 minutes and 7 .2 minutes respectively.
00:36
Now, the range of the data was 13 minutes and the fastest anyone was checked out was 1 more in 1 minute.
00:42
Now, first part of this question is what was the longest time anyone waited in the line.
00:47
Now, here, the total customers is equal to 200.
00:55
Now range of the data is given as 13 here the minimum value is 1 .1 right now we know the formula that is range is equal to the maximum value minus the minimum value right so from this we can determine the maximum value so the maximum value this will be equal to range plus the minimum value right so this is equal to 13 plus 1 .1 that is equal to 14 .1 right so the longest time anyone waited in line was is 14 .1 minutes.
01:29
Now the next part of this question is that approximately how many customers waited 7 .2 minutes or less to be checked out.
01:38
Now here the 90th percentile is equal to 9 .7.
01:47
So we say that k here is 9 .7.
01:50
Now k minus a into 1 upon b minus a is equal to 0 .90 right so this will be 9 .7 minus a upon b minus a is equal to 0 .90 that is 9 .7 minus a is equal to 0 .90 b minus 0 .90 a or 9 .7 is equal to 0 .90 b plus 0 .10a right now now the 60th percentile here is equal to 7 .2...