A supplier of kerosene has a weekly demand Y possessing a probability density function given by U=20Y-9UE(U)E(U)=E(U)E(U)= This is all im given
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The pdf is given by U = 20Y - 9U. We are also given that E(U) is the expected value of U, and it is equal to itself, i.e., E(U) = E(U). Show more…
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A supplier of kerosene has a weekly demand $Y$ possessing a probability density function given by $$f(y)=\left\{\begin{array}{ll} y, & 0 \leq y \leq 1 \\ 1, & 1<y \leq 1.5 \\ 0, & \text { elsewhere } \end{array}\right.$$ with measurements in hundreds of gallons. (This problem was introduced in Exercise $4.13 .$ ) The supplier's profit is given by $U=10 Y-4$ a. Find the probability density function for $U$ b. Use the answer to part (a) to find $E(U)$. c. Find $E(U)$ by the methods of Chapter 4
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A supplier of kerosene has a weekly demand Y possessing a probability density function given by f(y) = {y, 0 ≤ y ≤ 1; 1, 1 < y ≤ 1.5; 0, elsewhere, with measurements in hundreds of gallons. (This problem was introduced in Exercise 4.13.) The supplier's profit is given by U = 10Y - 4. a Find the probability density function for U. b Use the answer to part (a) to find E(U).
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