Question

a survey of 388 randomly chosen office workers showed that while they spend on average of 1.8 hours not working while on the clock each week. the standard deviation is 0.6 hours. a) the margin of error is 0.061 b) find the 95% confidence interval estimating the actual mean number of hours all office workers spend jot working while on the clock each week. round to 3 decimal places

Name: a survey of 388 randomly chosen office workers showed that while they spend on average of 18 hours not working while on the clock each week the standard deviation is 06 hours a the margin of 95831
Uploaded: 2023-07-29T15:59:37-08:00
Duration: 2 min 58 s
Channel: Joanna Quigley
Description: a survey of 388 randomly chosen office workers showed that while they spend on average of 18 hours not working while on the clock each week the standard deviation is 06 hours a the margin of 95831

          a survey of 388 randomly chosen office workers showed that while they spend on average of 1.8 hours not working while on the clock each week. the standard deviation is 0.6 hours. 
a) the margin of error is 0.061
b) find the 95% confidence interval estimating the actual mean number of hours all office workers spend jot working while on the clock each week. round to 3 decimal places

Added by Christopher N.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Joanna Quigley

07/29/2023

Step 1

For a 95% confidence interval, z* = 1.96. Plugging in the values given in the problem, we get: Margin of error = 1.96 * (0.6 / sqrt(388)) = 0.061 Show more…

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a survey of 388 randomly chosen office workers showed that while they spend on average of 1.8 hours not working while on the clock each week. the standard deviation is 0.6 hours. a) the margin of error is 0.061 b) find the 95% confidence interval estimating the actual mean number of hours all office workers spend jot working while on the clock each week. round to 3 decimal places