Question

A suspicious looking car (A) travels along a road at a constant velocity of 14.49 m/s. As it passes a parked, stationary police car (P), the police car accelerates from rest at 4 m/s2 in pursuit. I hate it when this happens! The police car continues to accelerate until it reaches a velocity of 18.49 m/s.

Name: a suspicious looking car a travels along a road at a constant velocity of 1449 ms as it passes a parked stationary police car p the police car accelerates from rest at 4 ms2 in pursuit i hat 53974
Uploaded: 2022-09-09T14:18:35-08:00
Duration: 2 min 7 s
Channel: Keondre Parker
Description: a suspicious looking car a travels along a road at a constant velocity of 1449 ms as it passes a parked stationary police car p the police car accelerates from rest at 4 ms2 in pursuit i hat 53974

          A suspicious looking car (A) travels along a road at a constant velocity of 14.49 m/s. As it passes a parked, stationary police car (P), the police car accelerates from rest at 4 m/s2 in pursuit. I hate it when this happens! The police car continues to accelerate until it reaches a velocity of 18.49 m/s.

Added by Brianna A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Keondre Parker

09/09/2022

Step 1

49 m/s from rest, given its acceleration of 4 m/s². Use the formula: \[ v = u + at \] where \( v \) is the final velocity (18.49 m/s), \( u \) is the initial velocity (0 m/s), \( a \) is the acceleration (4 m/s²), and \( t \) is the time. Rearranging the Show more…

Show all steps

Thanks for your feedback!

A suspicious looking car (A) travels along a road at a constant velocity of 14.49 m/s. As it passes a parked, stationary police car (P), the police car accelerates from rest at 4 m/s2 in pursuit. I hate it when this happens! The police car continues to accelerate until it reaches a velocity of 18.49 m/s.