00:01
In this question we will learn about the basic concepts of the equations of the motion.
00:06
The question is there is a swimmer and she is on the height of 1 .8 meters from the pool.
00:18
Right? she jumps with a velocity of 4 meter per second in the vertical direction.
00:30
Right? so there are three parts of the question.
00:34
In the first part we have to find the total time taken.
00:39
When she is in the air, in the second part we have to find the distance of the highest point above the board.
00:48
And in the third part we have to find the final velocity of the swimmer.
00:53
So let's solve the first part of the question, the total time taken, right? now we can take the initial and final position as difference.
01:03
So for the initial position, the initial position, the initial velocity is 4 meter per second, right? we don't know the final velocity, but what we know is the displacement in the wide direction, that is minus 1 .8 meter per second, sorry, meter, when she hits the water.
01:31
We also know the acceleration in y direction, that is gravity.
01:34
So we can use the second equation of motion to find the time taken, that is delta y is equals to ut plus half a t square.
01:49
We can substitute the values is equal to 4 t plus half minus 9 .8 t squared.
02:02
So this would form a quadratic equation and we can solve this quadratic equation to find the value of time taken.
02:09
So we can take the positive value of time, right? so t would be equal to 1 .14 seconds.
02:22
Now coming to the second part of the equation, that is the highest point above the board...