Question

A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f1 = 12.9 cm. The second lens is located at x = x2 = 81.47 cm and has a focal length of f2 = 19.4 cm. The tip of the object arrow is located at (x,y) = (xo,yo) = (-16.8 cm, 3.5 cm). 1) What is x1, the x co-ordinate of image of the arrow formed by the first lens? x1 = 7.3 cm x1 = 55.6 cm x1 = 0.018 cm 2) What is x3, the x co-ordinate of image of the arrow formed by the two lens system?

          A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f1 = 12.9 cm. The second lens is located at x = x2 = 81.47 cm and has a focal length of f2 = 19.4 cm. The tip of the object arrow is located at (x,y) = (xo,yo) = (-16.8 cm, 3.5 cm).

1) What is x1, the x co-ordinate of image of the arrow formed by the first lens?
x1 = 7.3 cm
x1 = 55.6 cm
x1 = 0.018 cm

2) What is x3, the x co-ordinate of image of the arrow formed by the two lens system?

A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f1 = 12.9 cm. The second lens is located at x = x2 = 81.47 cm and has a focal length of f2 = 19.4 cm. The tip of the object arrow is located at (x,y) = (xo,yo) = (-16.8 cm, 3.5 cm).

1) What is x1, the x co-ordinate of image of the arrow formed by the first lens?
x1 = 7.3 cm
x1 = 55.6 cm
x1 = 0.018 cm

2) What is x3, the x co-ordinate of image of the arrow formed by the two lens system?

Added by Andrew K.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Maitreya E

05/27/2022

Step 1

9 \, \text{cm} \) \( U_1 = -16.8 \, \text{cm} \) Substitute the values into the formula: \( \frac{1}{12.9} = \frac{1}{B_1} + \frac{1}{16.8} \) Solve for \( B_1 \): \( B_1 = \frac{1}{\frac{1}{12.9} + \frac{1}{16.8}} \) \( B_1 = \frac{1}{0.0775 + 0.0595} \) \( B_1 Show more…

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A system of two converging lenses forms an image of an arrow as shown. The first lens is located at x = 0 and has a focal length of f1 = 12.9 cm. The second lens is located at x = x2 = 81.47 cm and has a focal length of f2 = 19.4 cm. The tip of the object arrow is located at (x,y) = (xo,yo) = (-16.8 cm, 3.5 cm). 1) What is x1, the x co-ordinate of image of the arrow formed by the first lens? x1 = 7.3 cm x1 = 55.6 cm x1 = 0.018 cm