A system releases 622 kJ of heat and does 105 kJ of work on the surroundings. What is the change in internal energy of the system?
Added by Patrick F.
Step 1
ΔU = Q - W Given that the system releases 622 kJ of heat (Q = -622 kJ) and does 105 kJ of work on the surroundings (W = -105 kJ), we can substitute these values into the equation: ΔU = -622 kJ - (-105 kJ) ΔU = -622 kJ + 105 kJ ΔU = -517 kJ Show more…
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