00:01
Hi, to calculate the moment of inertia of the wheel, we need to use the formula i is equal to t minus f into r into t square divided by 4 pi square, where i is the moment of inertia of the wheel, t is the torque applied to the wheel, f is the tangential force applied to the rim of the wheel, r is the radius of the wheel which is half the diameter, t is the time taken for one revolution of the wheel.
00:35
First, let's calculate the values need for the formula.
00:39
The radius of the wheel is half the diameter, that is 80 centimeter divided by 2 which is equal to 40 centimeter or 0 .4 meter.
00:54
The tangential force applied to the rim of the wheel is 10 newton.
00:58
The time taken for one revolution of the wheel is t is equal to 1 .5 second.
01:07
To find the torque applied to the wheel, we need to know the angular acceleration of the wheel which can be calculated using the formula alpha is equal to delta omega divided by delta t, where alpha is the angular acceleration, delta omega is the change in angular velocity, delta t is the time taken for change in velocity.
01:28
Since the wheel starts from rest, the initial angular velocity is 0.
01:33
The final angular velocity is omega is equal to 2 pi by t...