00:01
Okay, so in this problem we have a tank that is filled with water at a depth of 20 centimeters and the bottom of the tank is a mirror.
00:17
Then a small fish floats motionless seven centimeters under the surface of the water.
00:27
So that seven centimeters is the distance of the object, in this case the fish from the mirror.
00:35
That is the real distance.
00:47
Now, question a asked, what is the apparent distance of the fish when viewed at normal incidence? so, the apparent object distance.
01:14
When viewed at normal incidence, we have this relationship.
01:24
The product of the real object distance and the index of refraction of air is equals to the product of the apparent object distance and the index of refraction of the water.
01:45
Then isolating the apparent object distance since this is what we're looking for, then we have this equation.
01:58
On...