00:02
Here in this question, a tank with a diameter of 10 meter is open to the top and contains water that is 12 meter deep.
00:07
So let us consider the top point as b and the there is a hole at the bottom with a diameter of 0 .02 meter which is at a height of 1 meter from the bottom.
00:20
So let us consider that point as a.
00:23
We need to use the bernoulli equation to find out the speed of the water as it exits the hole.
00:29
So the whole diameter is 0 .02 meter.
00:33
So let us find out the, let us first write the bernoulli equation.
00:38
So bernoulli equation is given by pa by roji plus va square by 2g plus za is equal to p2pb by rogy plus vb square by 2g plus zb.
00:50
So this is the bernoulli equation at two points a and b.
00:55
Now we need to write the values or the respective values.
00:59
Of pressure, velocity and the datum head so that we can calculate the unknown variables from this given equation.
01:08
So for bernoulli equations there are some assumptions, basic assumptions that are being followed and let us proceed further.
01:17
Here the datum head for point b is for point a is 1 meter and the datum head for point b is 12 meters.
01:28
That is, it is the distance between the bottom to the point a, which is 1 meter, and the distance between the bottom to the point b, which is 12 meters.
01:37
Next, the velocity at point b.
01:42
So, the water is steady and still at the point b.
01:46
That is why the velocity is zero at point b.
01:52
And the pressure at point a is the atmospheric pressure, as it is open to it, the hole is open to atmosphere...