A test is normally distributed with a mean of 70 and a standard deviation of 8. (a) What score would be needed to be in the 85th percentile? (b) What score would be needed to be in the 22nd percentile?
Added by Levi T.
Step 1
036 standard deviations above the mean. So, we calculate 1.036 * 8 (standard deviation) = 8.288. We then add this to the mean: 70 + 8.288 = 78.288. So, a score of approximately 78 would be needed to be in the 85th percentile. Show more…
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